- 2(5x-5)+5(2x+2)=
- 0
- 20x
- 20x-10
- 20x+10
- If x=a+2, and y=-8-a then x+y=
- 10
- 2a-6
- -10
- -6
- If x \ne -5, then \frac{x^{2}+3x-10}{x+5}-(x-2)=
- If (a-\frac{1}{a})^{2}=8, then a^{2}+\frac{1}{a^{2}}=
- 8
- 6
- 10
- 12
- (x+y)^{2}=16, and x^{2}+y^{2}=6 then xy=
- 5
- 10
- 6
- 4
- (x+y)=2, and x^{2}-y^{2}=6 then x-y=
- 12
- 4
- 6
- \frac{1}{3}
- \frac{15y+3}{3}-5y=
- 1
- 0
- 10y+1
- 3
- if b^{2}-a^{2}=9 then 5(a-b)(a+b)=
- \frac{9}{5}
- 4
- 50
- -45
- When c \ne 3, then \frac{c^{2}-9}{c-3}=
- c-3
- 1
- c+3
- 3-c
- If b>0, and b^{2}-1=10 \times 12, then b=
- 1
- 12
- 10
- 11
Answer Key 1 B 2 D 3 0 4 C 5 A 6 D 7 A 8 D 9 C 10 D
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