Pharmacy College Admission Test
- If $x=9$, then $3(x-3)^{2}=$
- $108$
- $112$
- $84$
- $94$
- $(a^{7})^{6}$
- $a^{13}$
- $a^{42}$
- $a^{7}$
- $a^{6}$
- What is the slop of the line that passes through $(-5,7)$ and $(2,-2)$?
- $\frac{9}{7}$
- $\frac{3}{7} $
- $-\frac{3}{7} $
- $\frac{-9}{7} $
- Factor: $x^{2}-4x-5$
- $(x-1)(x+5)$
- $(x+1)(x-5)$
- $(x+4)(x+1)$
- $(x-3)(x+4)$
- What is the y-intercept of the line expressed in the equation $2x+3y=6$?
- $3$
- $2 $
- $-2 $
- $\frac{2}{3} $
- Find the domain for the given function.
$f(x)=\log(x+5)$
- $(-5,\infty)$
- $[-5,\infty)$
- $(-\infty,5)$
- $[-\infty,5)$
- Which line is perpendicular to the y-axis?
- $x=6$
- $x=y-1$
- $y=x+1 $
- $y=1$
- $\lim_{x \to \infty}(\frac{9x^{5}-9x^{4}+3x^{3}+6x^{2}-x}{3x^{5}-5x^{2}})$
- $3$
- $ 0$
- $-3 $
- $\infty $
- $x^{2}+5=149$, $x=$
- $11,-11$
- $12,-12 $
- $14,-14 $
- None of the above
- $\lim_{x \to 3}(\frac{x^{2}-9}{x-3})$
- $0$
- $ \infty$
- $6 $
- $1 $
Answer Key
1 | A |
2 | B |
3 | D |
4 | B |
5 | B |
6 | A |
7 | D |
8 | A |
9 | B |
10 | C |
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