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math exams: CLEP College Algebra Practice Questions -- (Equations )
CLEP College Algebra Practice Questions -- (Equations )
- \frac{9}{x+5}=\frac{3}{x+1}
- 1
- 3
- 5
- 9
- 0
- xy+5y=10 and x+2=7, then y=
- 0
- 1
- 5
- 7
- 2
- \frac{9x}{5}=(a^{7}-1)^{3} and a=-1, solve for x.
- -40
- -\frac{40}{9}
- \frac{40}{9}
- \frac{35}{9}
- 0
- \frac{18}{x^{2}+6x+27}=1
- \{-3,3\}
- \{-3\}
- \{3\}
- \{-3,0\}
- \{-3,-3\}
- Find the solution of the following equation : |5x-1|=9
- \{2\}
- \{-\frac{8}{5}\}
- \{-\frac{8}{5},2\}
- \{\frac{9}{5}\}
- \{\frac{1}{5}\}
- If a=(b+5)^{2} and b=-5, what is a?
- -5
- 5
- 0
- 1
- 2
- Solve x^{2}+2x+11=0
- -1+\sqrt{10} or -1-\sqrt{10}
- 1+i\sqrt{10} or -1-i\sqrt{10}
- or -1-i\sqrt{10}
- -1+i\sqrt{10} or -1-i\sqrt{10}
- -1+i\sqrt{10}
- If \frac{a}{b}=5 then a^{2}-25b^{2}+7=
- 0
- 7
- -1
- 25
- 5
- Solve 9x-6 \leq 5x+2
- x \leq 2
- x \geq 2
- x \leq -2
- x \geq -2
- x < 2
- Solve \frac{3}{x}=\frac{2}{x-1}
- -3
- 2
- -2
- 3
- There is no solution
Answer Key
1 | A |
2 | B |
3 | B |
4 | E |
5 | C |
6 | C |
7 | D |
8 | B |
9 | A |
10 | D |
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