Processing math: 100%
Creative Commons License
This work is licensed under a Creative Commons Attribution-NonCommercial-NoDerivs 3.0 Unported License. math exams: SAT Practice Questions - 1

Thursday, June 23, 2011

SAT Practice Questions - 1

  1. 2(5x-5)+5(2x+2)=
    1. 0
    2. 20x
    3. 20x-10
    4. 20x+10
    5. 10x^{2}+20+x+20

  2. If x=a+2, and y=-8-a then x+y=

    1. 6
    2. 10
    3. 2a-6
    4. -10
    5. -6

  3. If x \ne -5, then \frac{x^{2}+3x-10}{x+5}-(x-2)=

  4. If (a-\frac{1}{a})^{2}=8, then a^{2}+\frac{1}{a^{2}}=

    1. 8
    2. 6
    3. 10
    4. 12
    5. 100

  5. (x+y)^{2}=16, and x^{2}+y^{2}=6 then xy=

    1. 5
    2. 10
    3. 6
    4. 4
    5. 16

  6. (x+y)=6, and x^{2}-y^{2}=2 then x-y=

    1. 12
    2. 4
    3. 6
    4. \frac{1}{3}
    5. 3

  7. \frac{15y+3}{3}-5y=

    1. 1
    2. 0
    3. 10y+1
    4. 3
    5. 3y+1


  8. if b^{2}-a^{2}=9 then 5(a-b)(a+b)=

    1. 45
    2. \frac{9}{5}
    3. 4
    4. 50
    5. -45

  9. When c \ne 3, then \frac{c^{2}-9}{c-3}=

    1. c-3
    2. 1
    3. c+3
    4. 3-c
    5. o

  10. If b>0, and b^{2}-1=10 \times 12, then b=

    1. 9
    2. 1
    3. 12
    4. 10
    5. 11


    Answer Key
    1 B
    2 E
    3 0
    4 C
    5 A
    6 D
    7 A
    8 E
    9 C
    10 E

1 comment:

  1. I believe you have two mistakes above:

    First: the answer to 6 is "E"
    y^2-x^2=(x+y)(x-y)
    since, (x+y)=2 and we have that y^2-x^2=6
    then, (x-y)=6/2
    the result, in turn, should be 3 NOT 1/3

    Second:
    In #8, the answer should be A

    Again, y^2-x^2=(x+y)(x-y)
    so, we have that y^2-x^2=9
    In turn, we know that (x+y)(x-y)=9 as well.
    So, 5(x+y)(x-y)= 5*9= 45 NOT -45

    Correct me if I'm wrong!XD

    ReplyDelete